60=5w^2

Solution for 60=5w^2 equation:

60=5w^2

We move all terms to the left:

60-(5w^2)=0

a = -5; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-5)·60
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*-5}=\frac{0-20\sqrt{3}}{-10}
=-\frac{20\sqrt{3}}{-10}
=-\frac{2\sqrt{3}}{-1}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*-5}=\frac{0+20\sqrt{3}}{-10}
=\frac{20\sqrt{3}}{-10}
=\frac{2\sqrt{3}}{-1}
$